Regex: match word that ends with "Id"

This may do the trick:

\b\p{L}*Id\b

Where \p{L} matches any (Unicode) letter and \b matches a word boundary.

How about \A[a-z]*Id\z? [This makes characters before Id optional. Use \A[a-z]+Id\z if there needs to be one or more characters preceding Id.]

Gumbo gets my vote, however, the OP doesn't specify whether just "Id" is an allowable word, which means I'd make a minor modification:

\w+Id\b

1 or more word characters followed by "Id" and a breaking space. The [a-zA-Z] variants don't take into account non-English alphabetic characters. I might also use \s instead of \b as a space rather than a breaking space. It would depend if you need to wrap over multiple lines.

Try this regular expression:

\w*Id\b

\w* allows word characters in front of Id and the \b ensures that Id is at the end of the word (\b is word boundary assertion).