Registry key Error: Java version has value '1.8', but '1.7' is required

After trying more than hundred of tricks, finally got success.

I removed all java.exe, javaw.exe and javaws.exe from my

1. Windows\System32 and

2. Windows\SysWOW64 folder. [Try step 2 if you have x64 system (Win 7 64 bits)]

In my case (Windows 7 64-bit), I just did the following:

• Removed the reference to C:\ProgramData\Oracle\Java\javapath; from the Path environment variable
• Removed files java, javaw and javaws from the C:\Windows\System32 folder

Afterwards, I closed all open command line consoles, reopened them and ran java -version.

re: Windows users

No. Don't remove the Javapath environment reference from your PATH variable.

The reason why the registry didn't work is that the Oracle Javapath script needs to run in the PATH sequence ahead of the JRE & JDK directories - it will sort out the current version:

put this directory at the HEAD of your %PATH% variable:

C:\ProgramData\Oracle\Java\javapath

[or wherever it is on your desktop]

so your PATH will look something like this - mine for example

PATH=C:\ProgramData\Oracle\Java\javapath;<other path directories>;E:\Program Files\Java\jdk1.8.0_77\bin;E:\Program Files\Java\jre1.8.0_77\bin

You will then see the correct, current version:

C:\>java -version
java version "1.8.0_77"
Java(TM) SE Runtime Environment (build 1.8.0_77-b03)
Java HotSpot(TM) 64-Bit Server VM (build 25.77-b03, mixed mode)

1. open regedit
2. go to [HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment]
3. change value CurrentVersion from "1.8" to "1.7"