Regular expression to extract numbers from a string

^\s*(\w+)\s*\(\s*(\d+)\D+(\d+)\D+\)\s*$

should work. After the match, backreference 1 will contain the month, backreference 2 will contain the first number and backreference 3 the second number.

Explanation:

^     # start of string
\s*   # optional whitespace
(\w+) # one or more alphanumeric characters, capture the match
\s*   # optional whitespace
\(    # a (
\s*   # optional whitespace
(\d+) # a number, capture the match
\D+   # one or more non-digits
(\d+) # a number, capture the match
\D+   # one or more non-digits
\)    # a )
\s*   # optional whitespace
$     # end of string

We can use \b as a word boundary like \b\d+\b.

you could use something like:

[^0-9]+([0-9]+)[^0-9]+([0-9]+).+

Then get the first and second capture groups.

if you know for sure that there are only going to be 2 places where you have a list of digits in your string and that is the only thing you are going to pull out then you should be able to simply use

\d+