Remove carriage return in Unix
I'm going to assume you mean carriage returns (CR, "\r"
, 0x0d
) at the ends of lines rather than just blindly within a file (you may have them in the middle of strings for all I know). Using this test file with a CR at the end of the first line only:
$ cat infile
hello
goodbye
$ cat infile | od -c
0000000 h e l l o \r \n g o o d b y e \n
0000017
dos2unix
is the way to go if it's installed on your system:
$ cat infile | dos2unix -U | od -c
0000000 h e l l o \n g o o d b y e \n
0000016
If for some reason dos2unix
is not available to you, then sed
will do it:
$ cat infile | sed 's/\r$//' | od -c
0000000 h e l l o \n g o o d b y e \n
0000016
If for some reason sed
is not available to you, then ed
will do it, in a complicated way:
$ echo ',s/\r\n/\n/
> w !cat
> Q' | ed infile 2>/dev/null | od -c
0000000 h e l l o \n g o o d b y e \n
0000016
If you don't have any of those tools installed on your box, you've got bigger problems than trying to convert files :-)
Old School:
tr -d '\r' < filewithcarriagereturns > filewithoutcarriagereturns
The simplest way on Linux is, in my humble opinion,
sed -i.bak 's/\r$//g' <filename>
-i will edit the file in place, while the .bak will create a backup of the original file by making a copy of your file and adding the extension .bak at the end. (You can specify what ever you want after the -i
, or specify only -i
to not create a backup.)
The strong quotes around the substitution operator 's/\r//'
are essential. Without them the shell will interpret \r
as an escape+r and reduce it to a plain r
, and remove all lower case r
. That's why the answer given above in 2009 by Rob doesn't work.
And adding the /g
modifier ensures that even multiple \r
will be removed, and not only the first one.
tr -d '\r' < infile > outfile
See tr(1)