Remove char at specific index - python

Use slicing, rebuilding the string minus the index you want to remove:

newstr = oldstr[:4] + oldstr[5:]

as a sidenote, replace doesn't have to move all zeros. If you just want to remove the first specify count to 1:

'asd0asd0'.replace('0','',1)

Out:

'asdasd0'

This is my generic solution for any string s and any index i:

def remove_at(i, s):
    return s[:i] + s[i+1:]