remove duplicates from sorted list code example

Example 1: python remove duplicates from list

mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)

Example 2: python remove duplicates

if mylist:
    mylist.sort()
    last = mylist[-1]
    for i in range(len(mylist)-2, -1, -1):
        if last == mylist[i]:
            del mylist[i]
        else:
            last = mylist[i]
# Quicker if all elements are hashables:
mylist = list(set(mylist))

Example 3: remove duplicates from sorted array

// Java
public int removeDuplicates(int[] nums) {
    if (nums.length == 0) return 0;
    int i = 0;
    for (int j = 1; j < nums.length; j++) {
        if (nums[j] != nums[i]) {
            i++;
            nums[i] = nums[j];
        }
    }
    return i + 1;
}

Example 4: remove duplicates from a list of lists python

k = [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4]]
new_k = []
for elem in k:
    if elem not in new_k:
        new_k.append(elem)
k = new_k
print k
# prints [[1, 2], [4], [5, 6, 2], [3]]

Example 5: remove duplicates in sorted array python

j = 0

// traverse elements of arr
for i=0 to n-2
    // if ith element is not equal to (i+1)th element of arr, then store ith value in arr[j]
    if arr[i] != arr[i+1]
        arr[j] = arr[i]
        j += 1

// store last value of arr in temp
arr[j] = arr[n-1]
j += 1

// print first j elements of array arr
for i=0 to j-1 
    print arr[i]

Example 6: remove duplicates from sorted array

def remove_duplicates(nums: [int]) -> int:
    cnt = 1
    for index in range(len(nums) - 1):
        if nums[index] != nums[index + 1]:
            nums[cnt] = nums[index + 1]
            cnt += 1
    print(cnt)