Remove duplicates in a list while keeping its order (Python)

use set(), then re-sort using the index of the original list.

>>> mylist = ['c','a','a','b','a','b','c']
>>> sorted(set(mylist), key=lambda x: mylist.index(x))
['c', 'a', 'b']

My answer to your other question, which you completely ignored!, shows you're wrong in claiming that

The answers of that question did not keep the "order"

• my answer did keep order, and it clearly said it did. Here it is again, with added emphasis to see if you can just keep ignoring it...:

Probably the fastest approach, for a really big list, if you want to preserve the exact order of the items that remain, is the following...:

biglist = [ 
    {'title':'U2 Band','link':'u2.com'}, 
    {'title':'ABC Station','link':'abc.com'}, 
    {'title':'Live Concert by U2','link':'u2.com'} 
]

known_links = set()
newlist = []

for d in biglist:
  link = d['link']
  if link in known_links: continue
  newlist.append(d)
  known_links.add(link)

biglist[:] = newlist