Remove Special Characters in NSString
Per comment of @Rostyslav Druzhchenko from on the selected answer of @MadhuP:
NSString *unfilteredString = @"!@#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet alphanumericCharacterSet] invertedSet];
NSString *escapedString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
NSLog (@"Result: %@", escapedString);
This is the answer that will use alphanumericCharacterSet
to handle multiple countries character set.
There are numerous ways of dealing with this. As an example, here's a solution using regular expressions. This is just an example. We don't know the entire range of special characters that you want to remove.
#import <Foundation/Foundation.h>
int main(int argc, const char * argv[])
{
@autoreleasepool {
NSRegularExpression *expression = [NSRegularExpression regularExpressionWithPattern:@"[,\\.`\"]"
options:0
error:NULL];
NSString *sampleString = @"The \"new\" quick brown fox, who jumped over the lazy dog.";
NSString *cleanedString = [expression stringByReplacingMatchesInString:sampleString
options:0
range:NSMakeRange(0, sampleString.length)
withTemplate:@""];
printf("cleaned = %s",[cleanedString UTF8String] );
}
return 0;
}
NSString *unfilteredString = @"!@#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"] invertedSet];
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
NSLog (@"Result: %@", resultString);
TRY THIS IT MAY HELPS YOU