Remove the 0b in binary

It's easy just make this function:

def f(n):print('{:0b}'.format(n))
f(17)
>>> 10001

use python string slice operation.

a = bin(17)
b = bin(17)[2:]

to format this to 8-bits use zfill.

c = b.zfill(8)

Use slice operation to remove the first two characters.

In [1]: x = 17

In [2]: y = bin(x)[2:]

In [3]: y
Out[3]: '10001'

Related