Removing fields from struct or hiding them in JSON Response

The question is asking for fields to be dynamically selected based on the caller-provided list of fields. This isn't possible to be done with the statically-defined json struct tag.

If what you want is to always skip a field to json-encode, then of course use json:"-" to ignore the field. (Note also that this is not required if your field is unexported; those fields are always ignored by the json encoder.) This isn't what the question asks.

To quote the comment on the json:"-" answer:

This [the json:"-" answer] is the answer most people ending up here from searching would want, but it's not the answer to the question.

I'd use a map[string]interface{} instead of a struct in this case. You can easily remove fields by calling the delete built-in on the map for the fields to remove.

That is, if you can't query only for the requested fields in the first place.

use `json:"-"`

// Field is ignored by this package.
Field int `json:"-"`

// Field appears in JSON as key "myName".
Field int `json:"myName"`

// Field appears in JSON as key "myName" and
// the field is omitted from the object if its value is empty,
// as defined above.
Field int `json:"myName,omitempty"`

// Field appears in JSON as key "Field" (the default), but
// the field is skipped if empty.
// Note the leading comma.
Field int `json:",omitempty"`

doc : http://golang.org/pkg/encoding/json/#Marshal

Another way to do this is to have a struct of pointers with the ,omitempty tag. If the pointers are nil, the fields won't be Marshalled.

This method will not require additional reflection or inefficient use of maps.

Same example as jorelli using this method: http://play.golang.org/p/JJNa0m2_nw