Removing HTTP and WWW from URL python

A more elegant solution would be using urlparse:

from urllib.parse import urlparse

def get_hostname(url, uri_type='both'):
    """Get the host name from the url"""
    parsed_uri = urlparse(url)
    if uri_type == 'both':
        return '{uri.scheme}://{uri.netloc}/'.format(uri=parsed_uri)
    elif uri_type == 'netloc_only':
        return '{uri.netloc}'.format(uri=parsed_uri)

The first option includes https or http, depending on the link, and the second part netloc includes what you were looking for.

You can use the string method replace:

url = 'http://www.google.com/images'
url = url.replace("http://www.","")

or you can use regular expressions:

import re

url = re.compile(r"https?://(www\.)?")
url = url.sub('', 'http://www.google.com/images').strip().strip('/')