Replace multiple strings in one gsub() or chartr() statement in R?
I'd go with the quite fast function stri_replace_all_fixed
from library(stringi):
library(stringi)
stri_replace_all_fixed("a'b c", pattern = c("'", " "), replacement = c("", "_"), vectorize_all = FALSE)
Here is a benchmark taking into account most of the other suggested solutions:
library(stringi)
library(microbenchmark)
library(gsubfn)
library(mgsub)
library(magrittr)
library(dplyr)
x_gsubfn <-
x_mgsub <-
x_nested_gsub <-
x_magrittr <-
x_stringi <- "a'b c"
microbenchmark("gsubfn" = { gsubfn(".", list("'" = "", " " = "_"), x_gsubfn) },
"mgsub" = { mgsub::mgsub(x_mgsub, c("'", " "), c("", "_")) },
"nested_gsub" = { gsub("Find", "Replace", gsub("Find","Replace", x_nested_gsub)) },
"magrittr" = { x_magrittr %<>% gsub("'", "", .) %>% gsub(" ", "_", .) },
"stringi" = { stri_replace_all_fixed(x_stringi, pattern = c("'", " "), replacement = c("", "_"), vectorize_all = FALSE) }
)
Unit: microseconds
expr min lq mean median uq max neval
gsubfn 458.217 482.3130 519.12820 513.3215 538.0100 715.371 100
mgsub 180.521 200.8650 221.20423 216.0730 231.6755 460.587 100
nested_gsub 14.615 15.9980 17.92178 17.7760 18.7630 40.687 100
magrittr 113.765 133.7125 148.48202 142.9950 153.0680 296.261 100
stringi 3.950 7.7030 8.41780 8.2960 9.0860 26.071 100
I am a fan of the syntax that the %<>%
and %>%
opperators from the magrittr
package provide.
library(magrittr)
x <- "a'b c"
x %<>%
gsub("'", "", .) %>%
gsub(" ", "_", .)
x
##[1] "ab_c"
gusbfn
is wonderful, but I like the chaining %>%
allows.
I know it is a bit old but it is hard to pass on an efficient base R solution. Just use the pipe:
test <- "abcegdfk461mnb"
test2 <- gsub("e|4|6","",test)
print(test2)
You can use gsubfn
library(gsubfn)
gsubfn(".", list("'" = "", " " = "_"), x)
# [1] "ab_c"
Similarly, we can also use mgsub
which allows multiple replacement with multiple pattern to search
mgsub::mgsub(x, c("'", " "), c("", "_"))
#[1] "ab_c"