return a pointer by reference c++ code example
Example 1: calling by reference and pointers c++
#include <iostream>
using namespace std;
void swap(int&, int&);
int main()
{
int a = 1, b = 2;
cout << "Before swapping" << endl;
cout << "a = " << a << endl;
cout << "b = " << b << endl;
swap(a, b);
cout << "\nAfter swapping" << endl;
cout << "a = " << a << endl;
cout << "b = " << b << endl;
return 0;
}
void swap(int& n1, int& n2) {
int temp;
temp = n1;
n1 = n2;
n2 = temp;
}
Example 2: calling by reference and pointers c++
#include <iostream>
using namespace std;
void swap(int*, int*);
int main()
{
int a = 1, b = 2;
cout << "Before swapping" << endl;
cout << "a = " << a << endl;
cout << "b = " << b << endl;
swap(&a, &b);
cout << "\nAfter swapping" << endl;
cout << "a = " << a << endl;
cout << "b = " << b << endl;
return 0;
}
void swap(int* n1, int* n2) {
int temp;
temp = *n1;
*n1 = *n2;
*n2 = temp;
}