Return HTML content as a string, given URL. Javascript Function
you need to return when the readystate==4 e.g.
function httpGet(theUrl)
{
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
return xmlhttp.responseText;
}
}
xmlhttp.open("GET", theUrl, false );
xmlhttp.send();
}
after you get the response just do call this function to append data to your body element
function createDiv(responsetext)
{
var _body = document.getElementsByTagName('body')[0];
var _div = document.createElement('div');
_div.innerHTML = responsetext;
_body.appendChild(_div);
}
@satya code modified as below
function httpGet(theUrl)
{
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
createDiv(xmlhttp.responseText);
}
}
xmlhttp.open("GET", theUrl, false);
xmlhttp.send();
}
The only one i have found for Cross-site, is this function:
<script type="text/javascript">
var your_url = 'http://www.example.com';
</script>
<script type="text/javascript" src="jquery.min.js" ></script>
<script type="text/javascript">
// jquery.xdomainajax.js ------ from padolsey
jQuery.ajax = (function(_ajax){
var protocol = location.protocol,
hostname = location.hostname,
exRegex = RegExp(protocol + '//' + hostname),
YQL = 'http' + (/^https/.test(protocol)?'s':'') + '://query.yahooapis.com/v1/public/yql?callback=?',
query = 'select * from html where url="{URL}" and xpath="*"';
function isExternal(url) {
return !exRegex.test(url) && /:\/\//.test(url);
}
return function(o) {
var url = o.url;
if ( /get/i.test(o.type) && !/json/i.test(o.dataType) && isExternal(url) ) {
// Manipulate options so that JSONP-x request is made to YQL
o.url = YQL;
o.dataType = 'json';
o.data = {
q: query.replace(
'{URL}',
url + (o.data ?
(/\?/.test(url) ? '&' : '?') + jQuery.param(o.data)
: '')
),
format: 'xml'
};
// Since it's a JSONP request
// complete === success
if (!o.success && o.complete) {
o.success = o.complete;
delete o.complete;
}
o.success = (function(_success){
return function(data) {
if (_success) {
// Fake XHR callback.
_success.call(this, {
responseText: data.results[0]
// YQL screws with <script>s
// Get rid of them
.replace(/<script[^>]+?\/>|<script(.|\s)*?\/script>/gi, '')
}, 'success');
}
};
})(o.success);
}
return _ajax.apply(this, arguments);
};
})(jQuery.ajax);
$.ajax({
url: your_url,
type: 'GET',
success: function(res) {
var text = res.responseText;
// then you can manipulate your text as you wish
alert(text);
}
});
</script>