return only the first dictionary inside a nested dictionary python code example

Example 1: make nested dict from two dict

data = [
    [14, 77766, [2, 2]],
    [15, 77766, [1, 2]],
    [70, 88866, [1, 5]],
    [71, 88866, [2, 5]],
    [72, 88866, [5, 5]],
    [73, 88866, [4, 5]],
    [74, 88866, [3, 5]],
    [79, 99966, [1, 2]],
    [80, 99966, [2, 2]],
]

c = {}
for key, id_, (value, _) in data:
    c.setdefault(id_, {})[key] = value
print(c)

Example 2: Nested dictionary Python

D = {'emp1': {'name': 'Bob', 'job': 'Mgr'},
     'emp2': {'name': 'Kim', 'job': 'Dev'},
     'emp3': {'name': 'Sam', 'job': 'Dev'}}

Example 3: python create nested dictionary

people = {1: {'name': 'John', 'age': '27', 'sex': 'Male'},
          2: {'name': 'Marie', 'age': '22', 'sex': 'Female'}}

print(people)