Return row of Data Frame based on value in a column - R

@Zelazny7's answer works, but if you want to keep ties you could do:

df[which(df$Amount == min(df$Amount)), ]

For example with the following data frame:

df <- data.frame(Name = c("A", "B", "C", "D", "E"), 
                 Amount = c(150, 120, 175, 160, 120))

df[which.min(df$Amount), ]
#   Name Amount
# 2    B    120

df[which(df$Amount == min(df$Amount)), ]
#   Name Amount
# 2    B    120
# 5    E    120

Edit: If there are NAs in the Amount column you can do:

df[which(df$Amount == min(df$Amount, na.rm = TRUE)), ]

Based on the syntax provided

 Select * Where Amount = min(Amount)

You could do using:

 library(sqldf)

Using @Kara Woo's example df

  sqldf("select * from df where Amount in (select min(Amount) from df)")
  #Name Amount
 #1    B    120
 #2    E    120

Use which.min:

df <- data.frame(Name=c('A','B','C','D'), Amount=c(150,120,175,160))
df[which.min(df$Amount),]

> df[which.min(df$Amount),]
  Name Amount
2    B    120

From the help docs:

Determines the location, i.e., index of the (first) minimum or maximum of a numeric (or logical) vector.