Robbers - square times square root

JavaScript (ES7), Neil

_26_=>_26_**6.25**.5

The hard part, of course, was figuring out what to do with all the extra characters. (And also not posting this solution in the wrong thread, like I accidentally did at first. Oopsie...)

Python, 15 bytes, Mr. Xcoder

lambda x:x**2.5

Pretty simple. Just takes x and raises it to the 2.5th power.

OCaml, 13 bytes, shooqie

fun f->f**2.5

Try it online!