Rotate an image around its center in canvas

just change the order of your code, i.e.,

ctx.rotate(...);

ctx.drawImage(...);

See a working example http://jsbin.com/owuyiq/

$(function () {
    var canvas = document.getElementById('logobg1');
    var ctx = canvas.getContext('2d');
    var img = new Image();

    var ang = 0; //angle
    var fps = 1000 / 25; //number of frames per sec
    img.onload = function () { //on image load do the following stuff
        canvas.width = this.width << 1; //double the canvas width
        canvas.height = this.height << 1; //double the canvas height
        var cache = this; //cache the local copy of image element for future reference
        setInterval(function () {
            ctx.save(); //saves the state of canvas
            ctx.clearRect(0, 0, canvas.width, canvas.height); //clear the canvas
            ctx.translate(cache.width, cache.height); //let's translate
            ctx.rotate(Math.PI / 180 * (ang += 5)); //increment the angle and rotate the image 
            ctx.drawImage(img, -cache.width / 2, -cache.height / 2, cache.width, cache.height); //draw the image ;)
            ctx.restore(); //restore the state of canvas
        }, fps);
    };

    img.src = 'http://i.stack.imgur.com/Z97wf.jpg?s=128'; //img
});

Based on the comments above, but a bit more simple and in vanilla. This one worked for me perfectly. Of course you should use clearRect in order to erase the canvas on each rendering.

var canvas = document.querySelector('#my-canvas');
var ctx = canvas.getContext('2d')
var ang = 0

function rotateAndRenderImg() {
    var img = document.querySelector('img')
    ctx.save()
    var pos = {x: desiredRenderPosX, y: desiredRenderPosY}
    ctx.translate(pos.x ,pos.y)    
    ctx.rotate(Math.PI / 180 * (ang += 5))
    ctx.drawImage(img, -img.width / 2, -img.height / 2, img.width, img.height)
    ctx.restore()
}