Run a JAR file from the command line and specify classpath

When you specify -jar then the -cp parameter will be ignored.

From the documentation:

When you use this option, the JAR file is the source of all user classes, and other user class path settings are ignored.

You also cannot "include" needed jar files into another jar file (you would need to extract their contents and put the .class files into your jar file)

You have two options:

1. include all jar files from the lib directory into the manifest (you can use relative paths there)
2. Specify everything (including your jar) on the commandline using -cp:
   java -cp MyJar.jar:lib/* com.somepackage.subpackage.Main

You can do these in unix shell:

java -cp MyJar.jar:lib/* com.somepackage.subpackage.Main

You can do these in windows powershell:

java -cp "MyJar.jar;lib\*" com.somepackage.subpackage.Main

Alternatively, use the manifest to specify the class-path and main-class if you like, so then you don't need to use -cp or specify the main class. In your case it would contain lines like this:

Main-Class: com.test.App
Class-Path: lib/one.jar lib/two.jar

Unfortunately you need to spell out each jar in the manifest (not a biggie as you only do once, and you can use a script to build the file or use a build tool like ANT or Maven or Gradle). And the reference has to be a relative or absolute directory to where you run the java -jar MyJar.jar.

Then execute it with

java -jar MyJar.jar

Run a jar file and specify a class path like this:

java -cp <jar_name.jar:libs/*> com.test.App

jar_name.jar is the full name of the JAR you want to execute

libs/* is a path to your dependency JARs

com.test.App is the fully qualified name of the class from the JAR that has the main(String[]) method

The jar and dependent jar should have execute permissions.