Run .exe file in Java from file location

You can use Runtime.exec(java.lang.String, java.lang.String[], java.io.File) where you can set the working directory.

Or else you can use ProcessBuilder as follows:

ProcessBuilder pb = new ProcessBuilder("myCommand", "myArg1", "myArg2");
pb.directory(new File("myDir"));
Process p = pb.start();

You don't need a console. You can execute a process using a working directory:

exec(String command, String[] envp, File dir)

Executes the specified string command in a separate process with the specified environment and working directory.

• command is the location of the .exe
• envp can be null
• dir, is the directory of your .exe

With respect to your code it should be...

Runtime.getRuntime().exec("c:\\program files\\test\\test.exe", null, new File("c:\\program files\\test\\"));

Another way of running a file is the following:

import java.awt.Desktop;
import java.io.File;

public static void open(String targetFilePath) throws IOException
{
    Desktop desktop = Desktop.getDesktop();

    desktop.open(new File(targetFilePath));
}

The the Standard Code for Running bat or any other through command line using java is :

runtimeProcess = Runtime.getRuntime().exec("cmd /c start cmd.exe /C\""+backup_path+"\"");
int processComplete = runtimeProcess.waitFor();

and you can go on continue for multiple files using & separator like: &&