is graphql id scalar int code example

Example 1: graphql nested schema

const StaffType = new GraphQLObjectType({
    name: 'Staff',
    fields: {
      id: {type: GraphQLInt},
      name: {type: GraphQLString},
      role: {type: GraphQLString},
      address: {type: AddressType}
    }
})

const AddressType = new GraphQLObjectType({
    name: 'Address',
    fields: {
      street: {type: GraphQLString},
      town: {type: GraphQLString}
    }
})

Example 2: graphql nested schema

`const MovieType = new GraphQLObjectType({
  name: 'Movie',
  fields: () => ({
    id: { type: GraphQLString },
    adult: { type: GraphQLBoolean },
    backdrop_path: { type: GraphQLString },
    belongs_to_collection: { type: BelongsToCollection },
    budget: { type: GraphQLInt },
    overview: { type: GraphQLString },
    popularity: { type: GraphQLInt },
    poster_path: { type: GraphQLString },
    production_companies: {
      type: new GraphQLList(CompaniesType)
    },
    genres: {
      type: new GraphQLList(GenreType)
    },
    release_date: { type: GraphQLString },
    tagline: { type: GraphQLString },
    title: { type: GraphQLString },
    vote_average: { type: GraphQLInt },
    vote_count: { type: GraphQLInt }
  })
});

const CompaniesType = new GraphQLObjectType({
  name: 'ProductionCompanies',
  fields: {
    id: { type: GraphQLInt },
    name: { type: GraphQLString },
    logo_path: { type: GraphQLString },
    original_country: { type: GraphQLString }
  }
});

const GenreType = new GraphQLObjectType({
  name: 'Genre',
  fields: () => ({
    id: { type: GraphQLInt },
    name: { type: GraphQLString }
  })
})

const BelongsToCollection = new GraphQLObjectType({
  name: 'BelongsToCollection',
  fields: () => ({
    id: { type: GraphQLInt },
    name: { type:  GraphQLString },
    poster_path: { type: GraphQLString },
    backdrop_path: { type: GraphQLString  } 
  })
});`