Separate octets of IP address using formulas
Here is classic one formula solution:
=TRIM(MID(SUBSTITUTE(A$1,".",REPT(" ",999)),(ROW()-1)*999-998,999))
"."
- is the delimiter.
(ROW()-1)
- gives nth item in delimited text.
More info at EXCELFOX
Here are four formulas you need
A2:=LEFT(A1,FIND(".",A1)-1)
A3:=MID(A1,FIND(".",A1)+1,FIND(".",A1,FIND(".",A1)+1)-FIND(".",A1)-1)
A4:=MID(A1,FIND(".",A1,FIND(".",A1)+1)+1,FIND(".",A1,FIND(".",A1,FIND(".",A1)+1)+1)-(FIND(".",A1,FIND(".",A1)+1)+1))
A5:=MID(A1,FIND(".",A1,FIND(".",A1,FIND(".",A1)+1)+1)+1,LEN(A1)-FIND(".",A1,FIND(".",A1,FIND(".",A1)+1)+1))
The FIND function has a third argument named start. So to find the second decimal point, you FIND a decimal point but you start where the first decimal point is plus one. It would be like this
=FIND(".",A1,4)
You start in 4 because your first decimal point is in position 3. But you don't know that, so you have to compute the '4'.
=FIND(".",A1,FIND(".",A1)+1)
Now to get 4, we find the first decimal and add 1. That's not too bad to find the second. But to find the third, you have to go another level. And the fourth is yet another level. It's hard to read and hard to maintain.
To make it a little easier, you can use helper columns.
A2 =LEFT(A1,C2-1)
C2 =FIND(".",A1)
A3 =MID(A1,C2+1,C3-C2-1)
C3 =FIND(".",A1,C2+1)
A4 =MID(A1,C3+1,C4-C3-1)
C4 =FIND(".",A1,C3+1)
A5 =MID(A1,C4+1,LEN(A1)-C4-1)
That way you're doing your FINDs in C and referring to those numbers in A.
If you don't like helper columns, and I don't, you could write a UDF like
Public Function FINDi(find_text As String, within_text As String, Optional instance As Long) As Long
Dim lReturn As Long
Dim i As Long
Const lFINDFIRST As Long = 0
If instance = lFINDFIRST Then
lReturn = InStr(1, within_text, find_text)
ElseIf instance < lFINDFIRST Then 'negative numbers finds last
lReturn = InStrRev(within_text, find_text)
Else
lReturn = 0
For i = 1 To instance
lReturn = InStr(lReturn + 1, within_text, find_text)
Next i
End If
FINDi = lReturn
End Function
and that gives you formulas like this
A2 =LEFT(A1,findi(".",A1)-1)
A3 =MID(A1,findi(".",A1)+1,findi(".",A1,2)-findi(".",A1,1)-1)
A4 =MID(A1,findi(".",A1,2)+1,findi(".",A1,3)-findi(".",A1,2)-1)
A5 =MID(A1,findi(".",A1,3)+1,LEN(A1)-findi(".",A1,3)-1)
Not as clean as the helper column, but self contained and definitely better than the built-in FIND.
Another UDF you could write duplicates what VBA's split function does.
Public Function SplitString(ByVal sInput As String, ByVal sDelim As String, ByVal lWhich As Long) As String
SplitString = Split(sInput, sDelim)(lWhich - 1)
End Function
That formula looks like
A2 =SplitString($A$1,".",ROW()-1)
A3 =SplitString($A$1,".",ROW()-1)
A4 =SplitString($A$1,".",ROW()-1)
A5 =SplitString($A$1,".",ROW()-1)