Separating **kwargs for different functions
If you add **kwargs
to all of the definitions, you can pass the whole lot:
def eat(food='eggs', how_much=1, **kwargs):
print(food * how_much)
def parrot_is(state='dead', **kwargs):
print("This parrot is %s." % state)
def skit(*lines, **kwargs):
for line in lines:
line(**kwargs)
Anything in **kwargs
that isn't also an explicit keyword argument will just get left in kwargs
and ignored by e.g. eat
.
Example:
>>> skit(eat, parrot_is, food='spam', how_much=50, state='an ex-parrot')
spamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspamspam
This parrot is an ex-parrot.
You can filter the kwargs
dictionary based on func_code.co_varnames
(in python 2) of a function:
def skit(*lines, **kwargs):
for line in lines:
line(**{key: value for key, value in kwargs.iteritems()
if key in line.func_code.co_varnames})
In python 3, __code__
should be used instead of func_code
. So the function will be:
def skit(*lines, **kwargs):
for line in lines:
line(**{key: value for key, value in kwargs.iteritems()
if key in line.__code__.co_varnames})
Also see: Can you list the keyword arguments a function receives?