bash print lines after line code example

Example: bash how to print lines after a matching line

# Basic syntax:
grep -A number word_to_match input_file
# This prints "number" number of lines after and including the first
# line that matches word_to_match in the input_file

# Note, the word_to_match can be any expression that grep uses for 
# 	identifying matches (e.g. including combinations of AND and OR, etc)