bash print rows that contain substring in field code example

Example: bash print rows that contain substring in field

# Basic syntax using awk:
awk -F'delimiter' 'index($field#, "substring")' input_file
# Where:
#	- -F'delimiter' is the delimiter used in the input_file
#	- index checks whether substring is found in the specified field. If
#		it is, that line is printed

# Example usage using awk:
# Say you have a file with the following lines and want to print lines 
# that contain the substring "target" in the second column
tab	separated	file	full
of	targeted	words	in
targeted	columns	of	text

# Running
awk -F'\t' 'index($2, "target")' input_file

# Would return:
of	targeted	words	in

# Note, you can use $0 to look for the substring in the whole row