how to get names of files in public folder javascript code example

Example 1: convert all files and folders in current directory into zip in linux

zip -r myfiles.zip mydir

Example 2: python script to read all file names in a folder

import os

def get_filepaths(directory):
    """
    This function will generate the file names in a directory 
    tree by walking the tree either top-down or bottom-up. For each 
    directory in the tree rooted at directory top (including top itself), 
    it yields a 3-tuple (dirpath, dirnames, filenames).
    """
    file_paths = []  # List which will store all of the full filepaths.

    # Walk the tree.
    for root, directories, files in os.walk(directory):
        for filename in files:
            # Join the two strings in order to form the full filepath.
            filepath = os.path.join(root, filename)
            file_paths.append(filepath)  # Add it to the list.

    return file_paths  # Self-explanatory.

# Run the above function and store its results in a variable.   
full_file_paths = get_filepaths("/Users/johnny/Desktop/TEST")

Example 3: php get all php files in a directory

foreach(glob('includes/*.php') as $file) {
    ...
}

Example 4: how to get all folders on path in python

os.walk(directory)
[x[0] for x in os.walk(directory)]

Example 5: append a string in all files name linux

rename 's/^/1_/' *

where ^ is for starting of the file or end