Shell script change directory with variable

You variable contains a carriage return. Try saying:

cd $(echo $RED_INSTANCE_NAME | tr -d '\r')

and it should work. In order to remove the CR from the variable you can say:

RED_INSTANCE_NAME=$(echo $RED_INSTANCE_NAME | tr -d '\r')

---

The following would illustrate the issue:

$ mkdir abc
$ foo=abc$'\r'
$ echo "${foo}"
abc
$ cd "${foo}"
: No such file or directory
$ echo $foo | od -x
0000000 6261 0d63 000a
0000005
$ echo $foo | tr -d '\r' | od -x
0000000 6261 0a63
0000004
$ echo $'\r' | od -x
0000000 0a0d
0000002

One way to encounter your described problem is to have a tilde (~) in the variable name. Use the absolute path or $HOME variable instead. Note that using $HOME will require double quotations.

# doesn't work
$ vartilde='~/'
$ cd $vartilde
-bash: cd: ~: No such file or directory

# works
$ varfullpath='/Users/recurvirostridae'
$ cd $varfullpath

# works
$ varwithhome="$HOME"
$ cd $varwithhome

Try

cd "$RED_INSTANCE_NAME"

Also, make sure the path makes sense to the current directory where cd command is executed.