short data type in c code example

Example 1: how maany bytes in an int in C

[8-bit] signed char: -127 to 127
 [8-bit] unsigned char: 0 to 255
 [16-bit]signed short: -32767 to 32767
 [16-bit]unsigned short: 0 to 65535
 [32-bit]signed long: -2147483647 to 2147483647
 [32-bit]unsigned long: 0 to 4294967295
 [64-bit]signed long long: -9223372036854775807 to 9223372036854775807
 [64-bit]unsigned long long: 0 to 18446744073709551615

Example 2: c variable types

char	1 byte	-128 to 127 or 0 to 255
unsigned char	1 byte	0 to 255
signed char	1 byte	-128 to 127
int	2 or 4 bytes	-32,768 to 32,767 or -2,147,483,648 to 2,147,483,647
unsigned int	2 or 4 bytes	0 to 65,535 or 0 to 4,294,967,295
short	2 bytes	-32,768 to 32,767
unsigned short	2 bytes	0 to 65,535
long	8 bytes or (4bytes for 32 bit OS)	-9223372036854775808 to 9223372036854775807
unsigned long	8 bytes	0 to 18446744073709551615

Example 3: what is a long long int in c

#include 
#include 
#include 

#define FailedToEducate    101
#define Success            400

int main(void) {
	/* 
    	A long int is:
        	32-bit compiler: 
            	MIN: -2,147,483,648
            	MAX: 2,147,483,647
                unsigned MAX: 4,294,967,295
            64-bit compiler: 
            	MIN: -9,223,372,036,854,775,808
            	MAX: 9,223,372,036,854,775,807
                unsigned MAX: 18,446,744,073,709,551,615
        Therefore...a long int will either be
        -2,147,483,648 and 2,147,483,647 for a 32-bit compiler
        or -9,223,372,036,854,775,808 and 
        9,223,372,036,854,775,807 for a 64-bit compiler, 
        whilst a long long int will just be 
        -9,223,372,036,854,775,808 and 
        9,223,372,036,854,775,807
        
        I hope this made sense!
    */
  
  	bool userUnderstands=true;
  
  	if(userUnderstands) {
    	exit(Success);
    } else {
    	exit(FailedToEducate);
    }
}