Should __init__() call the parent class's __init__()?
If you need something from super's __init__
to be done in addition to what is being done in the current class's __init__,
you must call it yourself, since that will not happen automatically. But if you don't need anything from super's __init__,
no need to call it. Example:
>>> class C(object):
def __init__(self):
self.b = 1
>>> class D(C):
def __init__(self):
super().__init__() # in Python 2 use super(D, self).__init__()
self.a = 1
>>> class E(C):
def __init__(self):
self.a = 1
>>> d = D()
>>> d.a
1
>>> d.b # This works because of the call to super's init
1
>>> e = E()
>>> e.a
1
>>> e.b # This is going to fail since nothing in E initializes b...
Traceback (most recent call last):
File "<pyshell#70>", line 1, in <module>
e.b # This is going to fail since nothing in E initializes b...
AttributeError: 'E' object has no attribute 'b'
__del__
is the same way, (but be wary of relying on __del__
for finalization - consider doing it via the with statement instead).
I rarely use __new__.
I do all the initialization in __init__.
In Anon's answer:
"If you need something from super's __init__
to be done in addition to what is being done in the current class's __init__
, you must call it yourself, since that will not happen automatically"
It's incredible: he is wording exactly the contrary of the principle of inheritance.
It is not that "something from super's __init__
(...) will not happen automatically" , it is that it WOULD happen automatically, but it doesn't happen because the base-class' __init__
is overriden by the definition of the derived-clas __init__
So then, WHY defining a derived_class' __init__
, since it overrides what is aimed at when someone resorts to inheritance ??
It's because one needs to define something that is NOT done in the base-class' __init__
, and the only possibility to obtain that is to put its execution in a derived-class' __init__
function.
In other words, one needs something in base-class' __init__
in addition to what would be automatically done in the base-classe' __init__
if this latter wasn't overriden.
NOT the contrary.
Then, the problem is that the desired instructions present in the base-class' __init__
are no more activated at the moment of instantiation. In order to offset this inactivation, something special is required: calling explicitly the base-class' __init__
, in order to KEEP , NOT TO ADD, the initialization performed by the base-class' __init__
.
That's exactly what is said in the official doc:
An overriding method in a derived class may in fact want to extend rather than simply replace the base class method of the same name. There is a simple way to call the base class method directly: just call BaseClassName.methodname(self, arguments).
http://docs.python.org/tutorial/classes.html#inheritance
That's all the story:
when the aim is to KEEP the initialization performed by the base-class, that is pure inheritance, nothing special is needed, one must just avoid to define an
__init__
function in the derived classwhen the aim is to REPLACE the initialization performed by the base-class,
__init__
must be defined in the derived-classwhen the aim is to ADD processes to the initialization performed by the base-class, a derived-class'
__init__
must be defined , comprising an explicit call to the base-class__init__
What I feel astonishing in the post of Anon is not only that he expresses the contrary of the inheritance theory, but that there have been 5 guys passing by that upvoted without turning a hair, and moreover there have been nobody to react in 2 years in a thread whose interesting subject must be read relatively often.
In Python, calling the super-class' __init__
is optional. If you call it, it is then also optional whether to use the super
identifier, or whether to explicitly name the super class:
object.__init__(self)
In case of object, calling the super method is not strictly necessary, since the super method is empty. Same for __del__
.
On the other hand, for __new__
, you should indeed call the super method, and use its return as the newly-created object - unless you explicitly want to return something different.