Simpler way to check if variable is not equal to multiple string values?
For your first code, you can use a short alteration of the answer given by
@ShankarDamodaran using in_array()
:
if ( !in_array($some_variable, array('uk','in'), true ) ) {
or even shorter with []
notation available since php 5.4 as pointed out by @Forty in the comments
if ( !in_array($some_variable, ['uk','in'], true ) ) {
is the same as:
if ( $some_variable !== 'uk' && $some_variable !== 'in' ) {
... but shorter. Especially if you compare more than just 'uk' and 'in'. I do not use an additional variable (Shankar used $os) but instead define the array in the if statement. Some might find that dirty, i find it quick and neat :D
The problem with your second code is that it can easily be exchanged with just TRUE since:
if (true) {
equals
if ( $some_variable !== 'uk' || $some_variable !== 'in' ) {
You are asking if the value of a string is not A or Not B. If it is A, it is definitely not also B and if it is B it is definitely not A. And if it is C or literally anything else, it is also not A and not B. So that statement always (not taking into account schrödingers law here) returns true.
You can make use of in_array()
in PHP.
$os = array("uk", "us"); // You can set multiple check conditions here
if (in_array("uk", $os)) //Founds a match !
{
echo "Got you";
}