Sorting JSON by values

jQuery.fn.sort = function() {  
    return this.pushStack( [].sort.apply( this, arguments ), []);  
};  

 function sortLastName(a,b){  
     if (a.l_name == b.l_name){
       return 0;
     }
     return a.l_name> b.l_name ? 1 : -1;  
 };  
  function sortLastNameDesc(a,b){  
     return sortLastName(a,b) * -1;  
 };
var people= [
{
"f_name": "john",
"l_name": "doe",
"sequence": "0",
"title" : "president",
"url" : "google.com",
"color" : "333333",
},
{
"f_name": "michael",
"l_name": "goodyear",
"sequence": "0",
"title" : "general manager",
"url" : "google.com",
"color" : "333333",
}]

sorted=$(people).sort(sortLastNameDesc);  

Demo: https://jsfiddle.net/kvxazhso/

Successfully pass equal values (keep same order). Flexible : handle ascendant (123) or descendant (321), works for numbers, letters, and unicodes. Works on all tested devices (Chrome, Android default browser, FF).

Given data such :

var people = [ 
{ 'myKey': 'A', 'status': 0 },
{ 'myKey': 'B', 'status': 3 },
{ 'myKey': 'C', 'status': 3 },
{ 'myKey': 'D', 'status': 2 },
{ 'myKey': 'E', 'status': 7 },
...
];

Sorting by ascending or reverse order:

function sortJSON(arr, key, way) {
    return arr.sort(function(a, b) {
        var x = a[key]; var y = b[key];
        if (way === '123') { return ((x < y) ? -1 : ((x > y) ? 1 : 0)); }
        if (way === '321') { return ((x > y) ? -1 : ((x < y) ? 1 : 0)); }
    });
}

people2 = sortJSON(people,'status', '321'); // 123 or 321
alert("2. After processing (0 to x if 123; x to 0 if 321): "+JSON.stringify(people2));

jQuery isn't particularly helpful for sorting, but here's an elegant and efficient solution. Just write a plain JS function that takes the property name and the order (ascending or descending) and calls the native sort() method with a simple comparison function:

var people = [
    {
        "f_name": "john",
        "l_name": "doe",
        "sequence": "0",
        "title" : "president",
        "url" : "google.com",
        "color" : "333333",
    }
    // etc
];

function sortResults(prop, asc) {
    people.sort(function(a, b) {
        if (asc) {
            return (a[prop] > b[prop]) ? 1 : ((a[prop] < b[prop]) ? -1 : 0);
        } else {
            return (b[prop] > a[prop]) ? 1 : ((b[prop] < a[prop]) ? -1 : 0);
        }
    });
    renderResults();
}

Then:

sortResults('l_name', true);

Play with a working example here.