Sorting on the last field of a line

awk '{print $NF,$0}' file | sort | cut -f2- -d' '

Basically, this command does:

1. Repeat the last field at the beginning, separated with a whitespace (default OFS)
2. Sort, resolve the duplicated filenames using the full path ($0) for sorting
3. Cut the repeated first field, f2- means from the second field to the last

A one-liner in perl for reversing the order of the fields in a line:

perl -lne 'print join " ", reverse split / /'

You could use it once, pipe the output to sort, then pipe it back and you'd achieve what you want. You can change / / to / +/ so it squeezes spaces. And you're of course free to use whatever regular expression you want to split the lines.

something like this

awk '{print $NF"|"$0}' file | sort -t"|" -k1 | awk -F"|" '{print $NF }'

Here's a Perl command line (note that your shell may require you to escape the $s):

perl -e "print sort {(split '/', $a)[-1] <=> (split '/', $b)[-1]} <>"

Just pipe the list into it or, if the list is in a file, put the filename at the end of the command line.

Note that this script does not actually change the data, so you don't have to be careful about what delimeter you use.

Here's sample output:

>perl -e "print sort {(split '/', $a)[-1] <=> (split '/', $b)[-1]} " files.txt
/a/e/f/g/h/01-do-this-first
/a/b/c/10-foo
/a/b/c/20-bar
/a/d/30-bob
/a/b/c/50-baz
/a/e/f/g/h/99-local