Split string based on a regular expression

Its very simple actually. Try this:

str1="a    b     c      d"
splitStr1 = str1.split()
print splitStr1

When you use re.split and the split pattern contains capturing groups, the groups are retained in the output. If you don't want this, use a non-capturing group instead.

By using (,), you are capturing the group, if you simply remove them you will not have this problem.

>>> str1 = "a    b     c      d"
>>> re.split(" +", str1)
['a', 'b', 'c', 'd']

However there is no need for regex, str.split without any delimiter specified will split this by whitespace for you. This would be the best way in this case.

>>> str1.split()
['a', 'b', 'c', 'd']

If you really wanted regex you can use this ('\s' represents whitespace and it's clearer):

>>> re.split("\s+", str1)
['a', 'b', 'c', 'd']

or you can find all non-whitespace characters

>>> re.findall(r'\S+',str1)
['a', 'b', 'c', 'd']

The str.split method will automatically remove all white space between items:

>>> str1 = "a    b     c      d"
>>> str1.split()
['a', 'b', 'c', 'd']

Docs are here: http://docs.python.org/library/stdtypes.html#str.split