Splitting string with pipe character ("|")

split takes regex as a parameter.| has special meaning in regex.. use \\| instead of | to escape it.

Using Pattern.quote()

String[] value_split = rat_values.split(Pattern.quote("|"));

//System.out.println(Arrays.toString(rat_values.split(Pattern.quote("|")))); //(FOR GETTING OUTPUT)

Using Escape characters(for metacharacters)

String[] value_split = rat_values.split("\\|");
//System.out.println(Arrays.toString(rat_values.split("\\|"))); //(FOR GETTING OUTPUT)

Using StringTokenizer(For avoiding regular expression issues)

public static String[] splitUsingTokenizer(String Subject, String Delimiters) 
{
     StringTokenizer StrTkn = new StringTokenizer(Subject, Delimiters);
     ArrayList<String> ArrLis = new ArrayList<String>(Subject.length());
     while(StrTkn.hasMoreTokens())
     {
       ArrLis.add(StrTkn.nextToken());
     }
     return ArrLis.toArray(new String[0]);
}

Using Pattern class(java.util.regex.Pattern)

Arrays.asList(Pattern.compile("\\|").split(rat_values))
//System.out.println(Arrays.asList(Pattern.compile("\\|").split(rat_values))); //(FOR GETTING OUTPUT)

Output

[Food 1 ,  Service 3 ,  Atmosphere 3 ,  Value for money 1 ]

| is a metacharacter in regex. You'd need to escape it:

String[] value_split = rat_values.split("\\|");

Or.. Pattern#quote:

String[] value_split = rat_values.split(Pattern.quote("|"));

This is happening because String#split accepts a regex:

| has a special meaning in regex.

quote will return a String representation for the regex.