Sql - Explicit order of WHERE conditions?

Using a derived table:

SELECT *
FROM (
      SELECT *
      FROM INFORMATION_SCHEMA.TABLES
      WHERE ISNUMERIC(table_name)=1
     ) AS i
WHERE CAST(table_name AS INT)<>0

Alternatively, and most likely run in order, you can use a CASE statement:

SELECT *
FROM INFORMATION_SCHEMA.TABLES
WHERE 0<>(CASE WHEN ISNUMERIC(table_name)=1 
          THEN CAST(table_name AS INT)
          ELSE 0 END)

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It should be noted that for SQL Server there exist situations where the CASE-trick will fail. See the documentation on CASE, Remarks:

The CASE statement evaluates its conditions sequentially and stops with the first condition whose condition is satisfied. In some situations, an expression is evaluated before a CASE statement receives the results of the expression as its input. Errors in evaluating these expressions are possible. Aggregate expressions that appear in WHEN arguments to a CASE statement are evaluated first, then provided to the CASE statement. For example, the following query produces a divide by zero error when producing the value of the MAX aggregate. This occurs prior to evaluating the CASE expression.

WITH Data (value) AS 
( 
SELECT 0 
UNION ALL 
SELECT 1 
) 
SELECT 
   CASE 
      WHEN MIN(value) <= 0 THEN 0 
      WHEN MAX(1/value) >= 100 THEN 1 
   END 
FROM Data ;

I suspect this might also be true for other RDBMS implementations.