SQL Select Upcoming Birthdays
Liked the approach of @strelc, but his sql was a bit off. Here's an updated version that works well and is simple to use:
SELECT * FROM User
WHERE (DATEDIFF(dd, getdate(), DATEADD(yyyy,
DATEDIFF(yyyy, birthdate, getdate()) + 1, birthdate)) + 1) % 366 <= <number of days>
edit 10/2017: add single day to end
Best use of datediff and dateadd. No rounding, no approximates, no 29th of february bug, nothing but date functions
ageOfThePerson = DATEDIFF(yyyy,dateOfBirth, GETDATE())
dateOfNextBirthday = DATEADD(yyyy,ageOfThePerson + 1, dateOfBirth)
daysBeforeBirthday = DATEDIFF(d,GETDATE(), dateofNextBirthday)
Thanks to @Gustavo Cardoso, new definition for the age of the person
ageOfThePerson = FLOOR(DATEDIFF(d,dateOfBirth, GETDATE())/365.25)
In case someone is still looking for a solution in MySQL (slightly different commands), here's the query:
SELECT
name,birthday,
FLOOR(DATEDIFF(DATE(NOW()),birthday) / 365.25) AS age_now,
FLOOR(DATEDIFF(DATE_ADD(DATE(NOW()),INTERVAL 30 DAY),birthday) / 365.25) AS age_future
FROM user
WHERE 1 = (FLOOR(DATEDIFF(DATE_ADD(DATE(NOW()),INTERVAL 30 DAY),birthday) / 365.25)) - (FLOOR(DATEDIFF(DATE(NOW()),birthday) / 365.25))
ORDER BY MONTH(birthday),DAY(birthday)
Note: I've edited this to fix what I believe was a significant bug. The currently posted version works for me.
This should work after you modify the field and table names to correspond to your database.
SELECT
BRTHDATE AS BIRTHDAY
,FLOOR(DATEDIFF(dd,EMP.BRTHDATE,GETDATE()) / 365.25) AS AGE_NOW
,FLOOR(DATEDIFF(dd,EMP.BRTHDATE,GETDATE()+7) / 365.25) AS AGE_ONE_WEEK_FROM_NOW
FROM
"Database name".dbo.EMPLOYEES EMP
WHERE 1 = (FLOOR(DATEDIFF(dd,EMP.BRTHDATE,GETDATE()+7) / 365.25))
-
(FLOOR(DATEDIFF(dd,EMP.BRTHDATE,GETDATE()) / 365.25))
Basically, it gets the # of days from their birthday to now, and divides that by 365 (to avoid rounding issues that come up when you convert directly to years).
Then it gets the # of days from their birthday to a week from now, and divides that by 365 to get their age a week from now.
If their birthday is within a week, then the difference between those two values will be 1. So it returns all of those records.