SQL Server 2005 implementation of MySQL REPLACE INTO?

The functionality you're looking for is traditionally called an UPSERT. Atleast knowing what it's called might help you find what you're looking for.

I don't think SQL Server 2005 has any great ways of doing this. 2008 introduces the MERGE statement that can be used to accomplish this as shown in: http://www.databasejournal.com/features/mssql/article.php/3739131 or http://blogs.conchango.com/davidportas/archive/2007/11/14/SQL-Server-2008-MERGE.aspx

Merge was available in the beta of 2005, but they removed it out in the final release.

This is something that annoys me about MSSQL (rant on my blog). I wish MSSQL supported upsert.

@Dillie-O's code is a good way in older SQL versions (+1 vote), but it still is basically two IO operations (the exists and then the update or insert)

There's a slightly better way on this post, basically:

--try an update
update tablename 
set field1 = 'new value',
    field2 = 'different value',
    ...
where idfield = 7

--insert if failed
if @@rowcount = 0 and @@error = 0
    insert into tablename 
           ( idfield, field1, field2, ... )
    values ( 7, 'value one', 'another value', ... )

This reduces it to one IO operations if it's an update, or two if an insert.

MS Sql2008 introduces merge from the SQL:2003 standard:

merge tablename as target
using (values ('new value', 'different value'))
    as source (field1, field2)
    on target.idfield = 7
when matched then
    update
    set field1 = source.field1,
        field2 = source.field2,
        ...
when not matched then
    insert ( idfield, field1, field2, ... )
    values ( 7,  source.field1, source.field2, ... )

Now it's really just one IO operation, but awful code :-(