SQL Server: SELECT only the rows with MAX(DATE)

If rownumber() over(...) is available for you ....

select OrderNO,
       PartCode,
       Quantity
from (select OrderNO,
             PartCode,
             Quantity,
             row_number() over(partition by OrderNO order by DateEntered desc) as rn
      from YourTable) as T
where rn = 1      

The best way is Mikael Eriksson, if ROW_NUMBER() is available to you.

The next best is to join on a query, as per Cularis' answer.

Alternatively, the most simple and straight forward way is a correlated-sub-query in the WHERE clause.

SELECT
  *
FROM
  yourTable AS [data]
WHERE
  DateEntered = (SELECT MAX(DateEntered) FROM yourTable WHERE orderNo = [data].orderNo)

Or...

WHERE
  ID = (SELECT TOP 1 ID FROM yourTable WHERE orderNo = [data].orderNo ORDER BY DateEntered DESC)

select OrderNo,PartCode,Quantity
from dbo.Test t1
WHERE EXISTS(SELECT 1
         FROM dbo.Test t2
         WHERE t2.OrderNo = t1.OrderNo
           AND t2.PartCode = t1.PartCode
         GROUP BY t2.OrderNo,
                  t2.PartCode
         HAVING t1.DateEntered = MAX(t2.DateEntered))

This is the fastest of all the queries supplied above. The query cost came in at 0.0070668.

The preferred answer above, by Mikael Eriksson, has a query cost of 0.0146625

You may not care about the performance for such a small sample, but in large queries, it all adds up.