size of tables in sql server code example
Example: sql server table size
SELECT
s.Name AS SchemaName,
t.NAME AS TableName,
p.rows AS RowCounts,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB desc
;
SELECT
OBJECT_NAME(i.OBJECT_ID) AS NomTaula
, i.name AS NomIndex
, SUM(a.used_pages) * 8 / 1024 AS TamanyMB
FROM
sys.indexes AS i
, sys.partitions AS p
, sys.allocation_units AS a
WHERE
i.OBJECT_ID = p.OBJECT_ID
AND i.index_id = p.index_id
AND p.partition_id = a.container_id
AND i.is_primary_key = 0
GROUP BY
i.OBJECT_ID
, i.index_id
, i.name
ORDER BY
TamanyMB DESC,
NomTaula,
i.index_id
;