sql get difference between two dates code example

Example 1: mysql date diff

SELECT DATEDIFF(expr1,expr2) as difference_in_days;


select DATEDIFF('2020-05-15', '2020-05-10'); //returns 5
select DATEDIFF('2020-05-13', '2020-05-16'); //returns -3
select DATEDIFF('2020-06-30', '2020-05-30'); //returns 30

Example 2: sql select between two dates

select Date, TotalAllowance from Calculation where EmployeeId = 1
             and Date between '2011/02/25' and '2011/02/27'

Example 3: date difference in number of days sql server

DECLARE 
    @start_dt DATETIME2= '2019-12-31 23:59:59.9999999', 
    @end_dt DATETIME2= '2020-01-01 00:00:00.0000000';

SELECT 
    DATEDIFF(year, @start_dt, @end_dt) diff_in_year, 
    DATEDIFF(quarter, @start_dt, @end_dt) diff_in_quarter, 
    DATEDIFF(month, @start_dt, @end_dt) diff_in_month, 
    DATEDIFF(dayofyear, @start_dt, @end_dt) diff_in_dayofyear, 
    DATEDIFF(day, @start_dt, @end_dt) diff_in_day, 
    DATEDIFF(week, @start_dt, @end_dt) diff_in_week, 
    DATEDIFF(hour, @start_dt, @end_dt) diff_in_hour, 
    DATEDIFF(minute, @start_dt, @end_dt) diff_in_minute, 
    DATEDIFF(second, @start_dt, @end_dt) diff_in_second, 
    DATEDIFF(millisecond, @start_dt, @end_dt) diff_in_millisecond;

Example 4: find difference in dates sql

SELECT DATEDIFF(day, date1,date2) AS DateDiff
/*
DATEDIFF accepts three arguments
1- day, month, year etc what form you need difference
2,3- dates 
*/

Example 5: postgresql get difference between two dates

select age('2010-04-01', '2012-03-05'),
       date_part('year',age('2010-04-01', '2012-03-05')),
       date_part('month',age('2010-04-01', '2012-03-05')),
       date_part('day',age('2010-04-01', '2012-03-05'));

Example 6: difference in dates sql

SELECT (END_DATE - START_DATE) Days-Total FROM MyTable
/*this works for oracle sql*/