table for all primary keys code example

Example 1: identify primary key in sql table

-- NOTE: this is for SQL-Oracle specifically

-- syntax:
SELECT cols.table_name, cols.column_name, cols.position, cons.status, cons.owner
FROM all_constraints cons, all_cons_columns cols
WHERE cols.table_name = '<table-name>' -- Replace <table-name> with your table-name
AND cons.constraint_type = 'P'
AND cons.constraint_name = cols.constraint_name
AND cons.owner = cols.owner


-- example:
SELECT cols.table_name, cols.column_name, cols.position, cons.status, cons.owner
FROM all_constraints cons, all_cons_columns cols
WHERE cols.table_name = 'CUSTOMERS' 
AND cons.constraint_type = 'P'
AND cons.constraint_name = cols.constraint_name
AND cons.owner = cols.owner

Example 2: Get a list of tables and the primary key

select schema_name(tab.schema_id) as [schema_name], 
    tab.[name] as table_name, 
    pk.[name] as pk_name,
    substring(column_names, 1, len(column_names)-1) as [columns]
from sys.tables tab
    left outer join sys.indexes pk
        on tab.object_id = pk.object_id 
        and pk.is_primary_key = 1
   cross apply (select col.[name] + ', '
                    from sys.index_columns ic
                        inner join sys.columns col
                            on ic.object_id = col.object_id
                            and ic.column_id = col.column_id
                    where ic.object_id = tab.object_id
                        and ic.index_id = pk.index_id
                            order by col.column_id
                            for xml path ('') ) D (column_names)
order by schema_name(tab.schema_id),
    tab.[name]