Start Windows batch file maximized

You can try start /MAX yourscript.bat to start your script in a maximized cmd (up to Windows 7)

Edit (by Rik):

I've created a small example which shows how you could do it all in one batch-file
(without a separate launcher):

@echo off
if not "%1" == "max" start /MAX cmd /c %0 max & exit/b

:: here comes the rest of your batch-file
echo "test"

pause

There will be a slight flicker of the original batch-file (which will exit immediately) before starting the maximized version.

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Simple explanation:
If the batch is not called with the parameter max we call itself again (%0), this time maximized with the help of start /max, and with the parameter max and that way the second time its called it will skip the if-statement and continue with your commands.

Breakdown:

• if not "%1" == "max" execute the next command only if %1 is not "max". %1 stands for the first parameter given to the batch-file. So my_batch.bat max will have max in the %1-variable. If we didn't start the batch with a max parameter we need to execute this line.
• start /MAX start the command after it, in maximized form.
• cmd /c execute cmd.exe and /c means exit afterwards.
• %0 max. The %0 stands for your own batch-file name and here max is its first parameter. This means we need to skip that first if-line or else we get caught in a loop :)
• & exit/b: The & means execute the next command simultaneous with the previous. This means we executed the start /max your batchfile and in the meantime exit the current batch.

This also means we can't call this version with any other parameters than max. If your batch-files needs a parameter to start then you'll need to do some more magic (like shifting the %1 after testing).
If that's the case let us know.