Swift UIFont IBInspectable - is it possible?
I have done this way
fileprivate var _fontSize:CGFloat = 18
@IBInspectable
var font:CGFloat
{
set
{
_fontSize = newValue
lblPlaceholder.font = UIFont(name: _fontName, size: _fontSize)
}
get
{
return _fontSize
}
}
fileprivate var _fontName:String = "Helvetica"
@IBInspectable
var fontName:String
{
set
{
_fontName = newValue
lblPlaceholder.font = UIFont(name: _fontName, size: _fontSize)
}
get
{
return _fontName
}
}
Idea
You can use Int enums to select one of the certain fonts.
Details
xCode 8.2.1, Swift 3
Code
enum FontType: Int
import UIKit
enum FontType: Int {
case Default = 0, Small, Large
var fount: UIFont {
switch self {
case .Default:
return UIFont.systemFont(ofSize: 17)
case .Small:
return UIFont.systemFont(ofSize: 12)
case .Large:
return UIFont.systemFont(ofSize: 24)
}
}
static func getFont(rawValue: Int) -> UIFont {
if let fontType = FontType(rawValue: rawValue) {
return fontType.fount
}
return FontType.Default.fount
}
}
class View: UIView
import UIKit
@IBDesignable
class View: UIView {
private var label: UILabel!
@IBInspectable var textFont:Int = 0
override func draw(_ rect: CGRect) {
super.draw(rect)
label = UILabel(frame: CGRect(x: 20, y: 20, width: 120, height: 40))
label.text = "Text"
label.textColor = .black
label.font = FontType.getFont(rawValue: textFont)
addSubview(label)
}
}
Main.storyboard