T-SQL: How to obtain the exact length of a string in characters?
Here's what I ended up using:
SELECT
CASE WHEN ((LEN ([t0].[Product] + '#') - 1) = 8)
THEN [t0].[Product] + 'test'
ELSE STUFF ([t0].[Product], 8, 0, 'test')
END
FROM [OrderItem] [t0]
Measurements indicate that the LEN (... + '#') - 1 trick is about the same speed as LEN (...) alone.
Thanks for all the good answers!
try this:
SELECT
CASE WHEN (LEN (REPLACE([t0].[Product],' ', '#') = 8)
THEN [t0].[Product] + 'test'
ELSE STUFF ([t0].[Product], 8, 0, 'test')
END
FROM [OrderItem] [t0]
Can't you look up the type information for the columns in the system tables?
If not then to determine whether or not a column is varchar
or nvarchar
this would do it.
create table #test
(
c varchar(50),
n nvarchar(50)
)
insert into #test values ('1,2,3,4 ',N'1,2,3,4,5 ')
SELECT
CASE
WHEN datalength(CAST(c AS nvarchar(MAX))) = datalength(c)
THEN 'c is nvarchar'
ELSE 'c is char'
END,
CASE
WHEN datalength(CAST(n AS nvarchar(MAX))) = datalength(n)
THEN 'n is nvarchar'
ELSE 'n is char'
END
FROM #test