New posts in Cubic Equations

Solve $\frac{x^3-4x^2-4x+16}{\sqrt{x^2-5x+4}}=0$

I've Hit a Major Snag While Writing a Paper on Deriving the Cubic Formula!

Given that $x_0$ is a real root of $x^3+px + q = 0$, how can I show that $p^2 \geq 4x_0q$?

Given that $f(x)$ is a polynomial of degree $3$, and its remainders are $2x - 5$ and $-3x + 4$ when divided by $x^2 - 1$ and $x^2 - 4$ respectively.

Using partial information to factor $x^6+3x^5+5x^4+10x^3+13x^2+4x+1.$

If $\alpha,\beta,\gamma$ are the roots of $x^3+x+1=0$, then find the equation whose roots are: $(\alpha-\beta)^2,(\beta-\gamma)^2,(\gamma-\alpha)^2$

Polynomial $x^3-2x^2-3x-4=0$

Can I solve this other than using Newton's sums or Newton's identities?

Given that $x_1, x_2, x_3$ are the roots of the polynomial $x^3-2x^2+3x+5=0$ find $(x_2-x_1)^2(x_3-x_1)^2(x_3-x_2)^2$.

Why should it be $\sqrt[3]{6+x}=x$?