New posts in Matrix Rank

$ A^2 - B^2 = I_{2n+1} \implies det(AB-BA)=0 $ where A,B are complex matrices of odd size

A problem regarding the rank of a matrix

$\text{det}(\text{abs}({\bf d - d}^T))$ being zero implies two or more elements equal in $\bf d$?

True/false: $\det(A^2+I)\ge 0$ for every $3 \times 3$ matrix with real entries and rank $>0$

$\operatorname{rank} A = \operatorname{rank} A^2$ if and only if $\lim_{\lambda \to 0} (A+\lambda I)^{-1}A$ exists

Proving $\operatorname{rank}A =\operatorname{rank}B$ when $AB = 2A + 3B$

Intuitive explanation of the rank-nullity theorem

Rank/determinant of the $n\times n$ matrix $((a_{ij}))$ where $a_{ij}=(i+j-1)^2$

How can I tell if a matrix is diagonalizable knowing only the trace, one eigenvalue, and a result of the characteristic polynomial?

Can one know the rank of a matrix product given the rank of one of them?