Test if a string has a period in it with bash

You can use pattern matching:

for i in $(drush site-alias) ; do
    if [[ $i == *.* ]] ; then
        drush "$i" command
    fi
done

With any Bourne-like shell, you'd write it:

case $i in
  *.*) drush "$i" command;;
esac

You can do this with a pattern replace expansion:

for i in $(drush site-alias); do
  if [ -z "${i//[^.]/}" ]; then
     # no period
     drush "$i" command
  fi
done

Yes, I quoted "$i", which is probably something you should do when possible, it avoids surprises. Though in this case it won't matter.

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