Test type of elements python tuple/list

all(isinstance(n, int) for n in lst)

Demo:

In [3]: lst = (1,2,3)

In [4]: all(isinstance(n, int) for n in lst)
Out[4]: True

In [5]: lst = (1,2,'3')

In [6]: all(isinstance(n, int) for n in lst)
Out[6]: False

Instead of isinstance(n, int) you could also use type(n) is int

Depending on what you're doing it may be more Pythonic to use duck typing. That way, things that are int-like (floats, etc.) can be passed as well as ints. In this case, you might try converting each item in the tuple to an int, and then catch any exceptions that arise:

>>> def convert_tuple(t, default=(0, 1, 2)):
...     try:
...         return tuple(int(x) for x in t)
...     except ValueError, TypeError:
...         return default
... 

Then you can use it like so:

>>> convert_tuple((1.1, 2.2, 3.3))
(1, 2, 3)
>>> convert_tuple((1.1, 2.2, 'f'))
(0, 1, 2)
>>> convert_tuple((1.1, 2.2, 'f'), default=(8, 9, 10))
(8, 9, 10)

you can also check type of elements using 'type' function in python like-

>>> all(type(n) == int for n in last) # [1, 2, 2, 34]
True
>>> all(type(n) == str for n in last) # [1, 2, 2, 34]
False

all(isinstance(i, int) for i in your_list))