the numbers in the array are odd numbers multiplied by the last odd number code example

Example 1: you are given an array of integers. your task is to print the sum of numbers that occurs for an even number of times in the array.

import collections
def fun(arr):
    mp = collections.defaultdict(int)
      
    for i in range(len(arr)):
        mp[arr[i]] += 1 
    sum = 0 
    for i in mp.keys(): 
          
        
        if (mp[i] % 2 == 0): 
            sum += i
    return sum
n= int(input())
arr = list(map(int,input().split()))
print(fun(arr))

Example 2: If there are an odd number of elements in the array, return the element in the middle of the array.

public String middleElement(String[] array)
{
    if (array.length >=1){
        if (array.length %2 != 0){
            return array[array.length/2];
        }
        else if(array.length %2 == 0){
            return array[array.length/2];
        }
        return "";
    }
    else return "";
}