Transparent UITableViewHeaderFooterView

Please forgive my inability to use stackoverflow....

Here's how I managed to implement it, using both these UITableviewDelegate methods:

- (void)tableView:(UITableView *)tableView willDisplayHeaderView:(UIView *)view forSection:(NSInteger)section {
  if ([view isMemberOfClass:[UITableViewHeaderFooterView class]]) {
    ((UITableViewHeaderFooterView *)view).backgroundView.backgroundColor = [UIColor clearColor];
  }
}

- (UIView *)tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section {
  UITableViewHeaderFooterView *feedHeaderView = [tableView dequeueReusableHeaderFooterViewWithIdentifier:@"HeaderIdentifier"];

  //Other customizations

  return feedHeaderView;
}

Hope that helps, took me forever to figure out. It seems the backgroundView is not created in the init so the color cannot be overridden there.

UPDATE: apparantly, my previously suggested answer wasn't working anymore in iOS 13+, here's what I would get in console -

Setting the background color on UITableViewHeaderFooterView has been deprecated. Please set a custom UIView with your desired background color to the backgroundView property instead.

Further, looking at some comments here, setting tintColor to .clear did the trick.

func tableView(_ tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int) {
        view.tintColor = .clear
}

Have fun coding :)

Make a view which has transparent background color and assign it to the UITableViewHeaderFooterView's backgroundView property.

class HeaderView: UITableViewHeaderFooterView{

    override
    init(reuseIdentifier: String?){
        super.init(reuseIdentifier: reuseIdentifier)
        self.backgroundView = UIView()
        self.backgroundView!.backgroundColor = UIColor.clearColor()
    }

    required
    init(coder: NSCoder){
        super.init(coder: coder)
    }

    override
    init(frame: CGRect){
        super.init(frame: frame)
    }
}